5x^2+6=36

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Solution for 5x^2+6=36 equation:



5x^2+6=36
We move all terms to the left:
5x^2+6-(36)=0
We add all the numbers together, and all the variables
5x^2-30=0
a = 5; b = 0; c = -30;
Δ = b2-4ac
Δ = 02-4·5·(-30)
Δ = 600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{600}=\sqrt{100*6}=\sqrt{100}*\sqrt{6}=10\sqrt{6}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-10\sqrt{6}}{2*5}=\frac{0-10\sqrt{6}}{10} =-\frac{10\sqrt{6}}{10} =-\sqrt{6} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+10\sqrt{6}}{2*5}=\frac{0+10\sqrt{6}}{10} =\frac{10\sqrt{6}}{10} =\sqrt{6} $

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